Question

If an any A.P. d=5 then t18-t13=?​

Answer 1

Answer:

t18=5*18

t13=5*13

=90-65

25

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hope this helps u, and good question by the way

Answer 2

The value is $t_{18}-t_{13}=25$

Step-by-step explanation:

Given : If an any A.P. d=5.

To find : The value of $t_{18}-t_{13}$ ?

Solution :

The nth term of A.P is $t_{n}=a+(n-1)d$

The 18th term is $t_{18}=a+17d$

The 13th term is $t_{13}=a+12d$

Substitute the values,

$t_{18}-t_{13}=a+17d-(a+12d)$

$t_{18}-t_{13}=a+17d-a-12d$

$t_{18}-t_{13}=5d$

Put the value d=5,

$t_{18}-t_{13}=5\times 5$

$t_{18}-t_{13}=25$

Therefore, the value is $t_{18}-t_{13}=25$

#Learn more

In an AP an= 3+5n. Find the AP​

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