Question

if an AP = a=10 d=1 then find a20​

Answer 1

Ans=29

Step-by-step explanation:

a = 10

d = 1

a20 = ?

By putting a,d in the formula, an = a + ( n - 1 ) d

We get, a20 = 10 + ( 20 - 1 ) 1

a20 = 10 + ( 19 × 1 )

a20 = 10 + 19

a20 = 29

Answer 2

Tn = a + (n-1) d

a=10 d=1 find a20

tn = a + (n-1) d

t²⁰ = 10 + (20-1) × 1

t²⁰ = 10 + 19×1

t²⁰ = 10 + 19

t²⁰ = 29