If an ap consists of n terms with first term a and the nth term l. Show that the sum of the nth term from the beginning and nth term from the end is a+ l
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Answered by
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nth term from the beginning = a+(n-1)d
nth term from the end = l - (n-1)d
sum = a+ (n-1)d + l - (n-1)d
a+l
hence proved
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Answered by
4
Answer:
a+l
Step-by-step explanation:
let the first term be A=a and last term An=l
then Sn= A+An (just 2 terms so simple addition)
substitute A & An
therefore...Sn =a+l
a+l
Step-by-step explanation:
let the first term be A=a and last term An=l
then Sn= A+An (just 2 terms so simple addition)
substitute A & An
therefore...Sn =a+l
done!!
Ya I got that thanks for ur help
thnq
u've done it wrong
how
see my answer
oh
i made it simpler...
no u didn't
u will get 0 for that
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