if an ap have 8 as first term and -5 as common difference and its first 3 terms are 8,A,B then A+B =
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Step-by-step explanation:
a=8
d=-5
Given that its, 1st term=8
2nd term=A= first term +common differnce(a+d).......1
3rd term=B=first term +2(common difference)(a+2d).......2
so putting values of a and d in ..1 and ...2
A=a+d
A=8+(-5)
A=8-5
A=3
B=a+2d
B=8+(2×-5)
B=8-10
B=-2
so putting values of A and B we get
A+B=3+(-2)
A+B=3-2
A+B=1
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