If an AP is 10,7,4........ -62, find the 11th term from its end.
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Here A. T. Q
a=10
d=7-10=-3
When we have time find t11 from end the we will reverse the AP
Therefore now AP will
-62, -59,.......................... 4,7,10
Now for this AP
A=-62
D=-(-3) =3now we will find t11 here,
T11=A+10D= -62+10(3) =-62+30=-32
Therefore T11 from end of real AP is -32 will be the answer
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