if an ap is 12 is -13 and the sum of first four terms is 24 what is the sum of first 10 term
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Step-by-step explanation:
if the 1st term is a and common difference is b then a+11b= -13
again 4/2{2a+(4-1).b}=24
2.(2a +3b)=24
2a+3b=24/2=12
again 2a+22b= -26
subtracting, -19b=38
b= -2
then a= -13 +22=9
the sum of 1st 10 term
10/2{2.9+(10-1).(-2)}
5(18+9.(-2)}
=5(18-18)=5.0=0
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