Question

if an ap s24=48 and s=35 the value of a24 is​

Answer 1

Answer:

Given:

Let the 1st term be a1, common difference be d and n=24

s24=48

sn = n/2[2a+(n-1)d]

s24 = 24/2[2a+(24-1)d]

48   = 12[2a+23d]

48 = 24a+126d

24a+126d = 48     ...............(1)

and

s?=35    

please avail the value of the value of ? here in order to complete the answer to this question.