Question

If an aqueous solution of weak monoprotic acid (Ka = 10-5) is diluted to 10 times, then K, will become O Doubled O 10 times 1 O Reduced by times 10 O Remains same​

Answer 1

will you get your correct answer

Answer 2

• pH =6

          $H^{+} =10^{6} M$

• After dilution

                     [$H^{+}$]  $=\frac{10^{-6} }{1000}$

                              $=10^{-9} M$

• ∴[$H^{+}$] from $H_{2} O_{}$  cannot be neglectd.

• total,

          [$H^{+}$] $=H^{-9} +10^{-7}$

                 $=10^{-7} (10^{-2} + 1)$

                 $=10^{-7} (1.01)$

• $pH=-log(1.01X10^{-7} )$

               $=7-0.0043$

                $=6.995$