Question

if an area of an isosceles right angled triangle is 32 cm square. then the length of its longest altitude is equal to?

Answer 1

let the equal sides be a
the by Pythagoras theorem
the base is √2a

area of a triangle=1/2bh
area =(1/2)*a*√2a=32
=√2a²=64
a²==64/√2=32√2
a=√[32*√2)=6.72cm

hope it helps