Question

If an article is aold at a profit of 15%instead of a profit of 9%the person gets 60rupees more.the costprice of the article(in rupees)is.

Answer 1

$\sf\large\underline{Let:}$

• $\rm{The\: cost\: price\:of\: article=x}$

$\sf\large\underline{To\: Find:}$

• $\rm{The\: cost\: price\:of\: article=?}$

$\sf\large\underline{Solution:}$

$\sf\underline{Given\:here:}$

• $\rm{The\: article\:is\:sold\:at\:a\: profit\:15\%}$
• $\rm{instead\:of\:9\%\:the\: person\:get\:Rs.60\:more}$

$\rm{\implies SP=\dfrac{100+G\%}{100}\times\:CP}$

$\rm{\implies SP=\dfrac{100+15}{100}\times\:x}$

$\rm{\implies SP=\dfrac{115x}{100}}$

$\rm{\implies SP=\dfrac{100+G\%}{100}\times\:CP}$

$\rm{\implies SP=\dfrac{100+9}{100}\times\:x}$

$\rm{\implies SP=\dfrac{109x}{100}}$

$\sf\large\underline{A.T.Q:}$

$\rm{\implies \dfrac{115x}{100}=\dfrac{109x}{100}+60}$

$\rm{\implies \dfrac{115x}{100}-\dfrac{109x}{100}=60}$

$\rm{\implies \dfrac{115x-109x}{100}=60}$

$\rm{\implies \dfrac{6x}{100}=60}$

$\rm{\implies 6x=60\times\:100}$

$\rm{\implies 6x=6000}$

$\rm{\implies x=1000}$

$\sf\large{Hence,}$

$\rm{\implies The\:cost\: price\:of\:the\: article=Rs.1000}$

Answer 2

Question:-

An article is aold at a profit of 15%instead of a profit of 9%the person gets 60rupees more.the costprice of the article.

Solution:-

According to the question:-

$= < \frac{115x}{100} = \frac{109}{100} + 60 \\ = > \frac{115x}{100} - \frac{109x}{100} = 60 \\ \\ = > \frac{115x - 109x}{100} = 60 \\ \\ = > 6x = 6000 \\ \\ = > x = rs.1000$

Therefore, The cost price of article =Rs.1000

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