Question

If an average person jogs, she produces 14.5 × 103 Cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 × 103 Cal for evaporation) is

A. 0.25 kg
B. 2.25 kg
C. 0.05 kg
D. 0.20 kg
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Answer 1

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Explanation:-

Given:

Calories produced in 1 minute = 1.45×10^3 cal/min amount of sweat

evaporated is equal to the rate of calories burned.

∴ Amount of sweat evaporated per minute=

$\frac{sweat \: produced \: per \ minute }{no. \: of \: calorie \: required \: for \: a evoporation \:per \: min }$

$= \frac{ 14.5 \times {10}^{3} }{ 580\times {10}^{3} }$

=0.25 kg

Hence option(a) is correct.

Thanks.!!

Answer 2

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