If an = {ax: a = n) then find 2n3n ( an = {ax:a e n) 06 2nn3n foof)
Ans. (a) 5n (b) n (c) 6n (d) None
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According to the given notation,
3N={3x:x∈R}={3,6,9,12.......}
and 7N={7x:x∈R}={7,14,21,28,35,42,.......}
Hence 3N∩7N={21,42,63}
={21x:x∈N}=21N
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