Question

If an denote the sum Of n term of an ap, then s12-s11 is the_term of the ap

Answer 1

Answer:

We are given a arithmetic progression.

denotes the sum of n terms of the A.P

Thus,

is the sum of 12 terms of AP

is the sum of first 11 terms of AP

Then,

= Sum of first 12 terms - Sum of first 11 terms

is the twelfth term of the AP

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Answer 2

Answer: a₁₂

Step-by-step explanation:

Sₙ= (n/2)*(2a + (n-1)d)

S₁₂= (12/2)*(2a + (12-1)d)

S₁₂= 6(2a + 11d) = 12a + 66d

Similarly,

S₁₁= 11(a + 5d) = 11a + 55d

So, S₁₂ - S₁₁ = 12a + 66d - 11a - 55d = a + 11d = a₁₂

Therefore, S₁₂ - S₁₁ = a₁₂

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