if an echo repeats 2 syllables.velocity of sound is 330 m/s.calculate the distance of reflecting surface
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the distance of reflecting surface = 330 m
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You haven't mentioned the time taken, so I am assuming it as 1 sec
Echo travels 2 times
So the distance will be 2d
Distance = Speed x Time
2d = 330 x 1
d = 330/2
d = 165m
Therefore the distance is 165 m
Echo travels 2 times
So the distance will be 2d
Distance = Speed x Time
2d = 330 x 1
d = 330/2
d = 165m
Therefore the distance is 165 m
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