if an edge of a cube is increased by 50% then its surface area increases to
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Let edge of cube = 2
Surface area = 4πr^2 = 16 π
Increase in edge = 50%
New edge = 2×(150/100) = 3
New surface area = 36π
Increase = 36π - 16π =20 π
%age increase = (20π/16π)×100
=125 %
Hope it helps
Surface area = 4πr^2 = 16 π
Increase in edge = 50%
New edge = 2×(150/100) = 3
New surface area = 36π
Increase = 36π - 16π =20 π
%age increase = (20π/16π)×100
=125 %
Hope it helps
Answered by
1
Let original edge of cube is x units.
Original surface area of cube = 6x^2 square units.
If edge of cube is increased by 50%, New edge of cube = x + (50/100) x = x + 0.5x = 1.5x units
New surface area of cube = 6 * (1.5x)^2 = 13.5x^2 square units.
Percentage increase in surface area =
((New Surace Area - Original Surface Area) /Original Surface Area) *100
= ((13.5x^2 - 6x^2)/6x^2) *100
= 125%
Original surface area of cube = 6x^2 square units.
If edge of cube is increased by 50%, New edge of cube = x + (50/100) x = x + 0.5x = 1.5x units
New surface area of cube = 6 * (1.5x)^2 = 13.5x^2 square units.
Percentage increase in surface area =
((New Surace Area - Original Surface Area) /Original Surface Area) *100
= ((13.5x^2 - 6x^2)/6x^2) *100
= 125%
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