Question

if an edge of a cube is increased by 50% then its surface area increases to

Answer 1

Let edge of cube = 2

Surface area = 4πr^2 = 16 π



Increase in edge = 50%

New edge = 2×(150/100) = 3

New surface area = 36π

Increase = 36π - 16π =20 π

%age increase = (20π/16π)×100

=125 %

Hope it helps

Answer 2

Let original edge of cube is x units.

Original surface area of cube = 6x^2 square units.

If edge of cube is increased by 50%, New edge of cube = x + (50/100) x = x + 0.5x = 1.5x units

New surface area of cube = 6 * (1.5x)^2 = 13.5x^2 square units.

Percentage increase in surface area =

((New Surace Area - Original Surface Area) /Original Surface Area) *100

= ((13.5x^2 - 6x^2)/6x^2) *100

= 125%