IF an effort of 400 newton is applied to pull a load of 320 Newton vertically up to 5 metre in 5 second, find V.R, M.A and efficiency of the machine.
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Load to be lifted = 400 N
Lord of moveable part = 5m × 5sec
=25 m/ sec
Mechanical advantage = No. of pulleys
Mechanical advantage = 400 ÷ 25
= 16
Hence , No. of pulleys = 16
Actual mechanical advantage = N-W/E
Where, w is load due to pulleys system effort
actual mechanical advantage = 16 - 320 ÷ 25
effiency. = 1 - W/ NE = 1 - 320 ÷ 6×25
= 1333.33 is the answer........✨
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