Question

If an electric appliance consumes 1000 J of energy in 50 s, Calculate the current flowing through that appliance when it is connected across 220 V voltage source.

Answer 1

Answer:

Explanation:

Given :

• Energy consumes by appliance (E) = 1000 J
• Time (T) = 50 s
• Potential difference (V) = 220 V

To Find :

• The current flowing through that appliance.

Formula to be used :

• E = I^2RT. { °.° Energy = Heat }
• Ohms law formula, ie,,.. V = IR

Solution :

★Making formulae,

⇒ E = I^2RT

⇒ E = I × I × R× T

{ °.° IR = V }

⇒ E = I × V × T

★Current,

E = I × V × T

⇒ 1000 = I × 220 × 50

⇒ 1000 = I × 11000

⇒ I = 1000/11000

⇒ I = 1/11

⇒ I = 0.0909 A

Hence, current flowing through that appliance is 0.0909 A.

Answer 2

$\huge\mathcal\colorbox{silver}{{\color{black}{★ANSWER★}}}$

$\huge\color{silver}{\textbf{\textsf{GIVEN :-}}}$

• Energy consumed by appliance (E) = 1000 J
• Time (T) = 50 s
• Potential difference (V) = 220 V

$\huge\color{silver}{\textbf{\textsf{TO FIND :-}}}$

• The current flowing through that appliance.

$\huge\color{silver}{\textbf{\textsf{FORMULA :-}}}$

• E = I^2RT
• Ohms law formula,i.e, V = IR

$\huge\color{silver}{\textbf{\textsf{SOLUTION :-}}}$

Making Formulae,

→ E = I^2RT

→ E = l × l × R × T

→ E = l × V × T

Current,

E = l × V × T

→ 1000 = l × 220 × 50

→ 1000 = l × 11000

→ l = 1000/11000

→ l = 0.0909 A

Hence, the current flowing through that appliance is 0.0909A.

Hope it Helps Buddy ♥️