If an electric appliance of rating (1000 W, 220 V) is used across 220 V for 1 hr, then the amount
of energy it will consume is
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Answer:
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Explanation:
Given : V = 220 volt, 1000 KVA
Time = 2hrs
(i) In kWh Energy consumed = Pt
= 2000 kWh
(ii) In joule
We know, 1kWh = 3.6 x 106 J
So, 2000 kWh = 2000 x 3.6 x 106/1
= 7.2 x 109 Joule = 7.2 x 109 J
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