Question

If an electric bulb is connected to a potential difference of 250 v and the current of 0.2 A past thought it then the power of the bulb will be

Answer 1

Answer:

Power=VI

power=250*0.2

power.=50kw/hr.

Answer 2

Answer

• Power of the bulb is 50 W

Given

• An electric bulb is connected to a potential difference of 250 v and the current of 0.2 A passed thought it

To Find

• Power of the bulb

Solution

Potential difference , V = 250 V

Current , I = 0.2 A

Power , P = ? W

We know that , " Power is defined as the product of potential difference and current "

⇒ Power , P = VI

⇒ P = 250 × 0.2

⇒ P = 25 × 2

⇒ P = 50 V-Ampere

⇒ P = 50 W