If an electric field is given by 10i+3j+4k,calculate the electric flux through a surface of area 10 units lying in yz plane
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abhi178:
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Answer:
The electric flux is 100 units.
Explanation:
Let us consider some OA and BC be any area which is lying on the yz plane
Therefore
Area of vector A=10i
Hence vector E=10i+3j+4k
We know that the flux=vector E x vector A
We also know that the area of the vector is perpendicular to the area of plane.
Therefore the area of vector E x vector A = 0
Now the net electric flux is due to the 10i
Net flux= vector E x vector A
Vector E=10i+3j+4k vector A=10i
Net flux=10i+3j+4k x 10i
=100+0+0
=100 units
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