Question

If an electric field of magnitude 250
NC is applied in the copper wire find
the
acceleration
electron
experienced by the rest​

Answer 1

Answer:

Electrostatic

Explanation:

Force = Charge ( Q ) × Electric Field ( E )

Mass ( m ) × acceleration ( a ) = Charge × Electric Field

Acceleration ( a ) = Charge × electric Field / mass

[ electron is given ]

a = 1.6 × 10-¹⁹ × 250 × 10-⁹ C / 9.1 × 10-³¹

= 400 × 10-²⁸ / 9.1 × 10-³¹

= 4 × 10-²⁶ × 10³¹ / 9.1

= 4 × 10⁵ / 9.1

acceleration ( a ) of electron in wire = 4.4 × 10⁴ m / s²