Question

If an electric field of magnitude 570Vm' is applied in the copper wire find the acceleration experienced by the electron?​

Answer 1

Given:

electric field E = 570 V/m

To find:

the acceleration experienced by the electron a =?

Step-to-step-explanation:

• We know that the force on the material is the product of a mass of material & acceleration.
• Mathematically force is expressed as

        F = ma                      ...(1)

        where

        F = force on the object

        m = mass of material

        t = acceleration

• This force is also defined as the product of a charge of electrons present in an electric field & a magnitude of an electric field in which force is applied.
• Mathematically this force is expressed as

       F = eE                        ...(2)

       where

       F = force on the object

       e = charge of electron

       E = magnitude of an electric field

       From equation (1) & (2)

       ma = eE                     ...(3)

• We have to find the acceleration experienced by the electron.  
• we know that a mass of electron m = 9.11 × 10⁻³¹ kg charges on electron e = 1.6 × 10⁻¹⁹ C

• Put these values in equation (3)

        9.11 × 10⁻³¹ × a = 1.6 × 10⁻¹⁹ × 570

• Solving the above equation we get

       a = 1.001 × 10¹⁴ m/s²

• The acceleration experienced by the electron is 1.001 × 10¹⁴ m/s².