Question

If an electric heater of 1KW used to heat 100kg of water at 30 degree celsius and supplies 3600000J of heat energy .Calculate the final temperature of water..

Answer 1

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60

o

C

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60

o

C,Q=msΔT

S= specific heat =4200J/kg

o

C

pt=msΔT

2000×t=200×4200×60

t=25200

or t=25.2×10

3

sec.

Hope it helps you

Please mark me as Brainliest and please follow me

Answer 2

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60

o

C

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60

o

C,Q=msΔT

S= specific heat =4200J/kg

o

C

pt=msΔT

2000×t=200×4200×60

t=25200

or t=25.2×10

3

sec.