If an electric iron of 1200 W is used for 2 hour every day, find electric energy consumed in the
month of 30 days.
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Answer:
72 kwh
Step-by-step explanation:
given ,
P= 1200W
t= 2h
total number of days = 30 days
E= P×t
= 1200× 2
= 2400Wh
energy consumed by 30 days = 2400× 30
= 72000 Wh
= 7.2 k W h
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