Question

If an electric iron of 1200 w is used for 30 minutes every day, dind the electricity consumed in the month of april

Answer 1

1200 w = 1.2 kW
30 min = 30/60 hr = 1/2 hr.
We know April has 30 days then the electricity consumed by the electric iron in 30 days -->
Power = energy/time
energy = power x time
= 1.2 kW x 1/2 h
= 0.6 kWh
Hope it helps!