Question

If an electric iron of 1200 W is used for 40 minutes every day, find the electric energy consumed in the month of March.

Answer 1

Answer:

Given that,

Power =1200W=1.2kWh

Time = 40 min / day × 40 days =0.5h×40= 15 h

Energy =Power×Time=1.2×15= 18kWh.

Answer 2

Answer:

This  is the solution

Explanation:

According to your numbers change it. But, these are the steps-

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