Question

If an electric iron of 1200W is used for 2 hours every day,

find the electric energy consumed in the month of April?

b) A force of 20 N displaces an object by 5m in the direction

of force, calculate the work done by the force?

c) Define power and give its SI unit. 5​

Answer 1

Answer:

given

energy consumed by an electric iron= 1200W

= 1200W/1000W = 1.2 kW (1KW = 1000W)

Explanation:

time ,t = 2h

we know that ,

energy = power x time =1.2kw x2h =2.4 kWh

energy consumed in one day = 2.4x1 =2.4KWh

there fore, energy consumed in the moth of april(i.e30 days) = 2.4 x30 =72kWh

(b) we know that ,

work = force x displacement = 20N x 5m

= 100J

(c) the rate of doing work is known as power

its S.I unit is Watt