Question

If an electric iron of 1600 W is used for 45 minutes everyday, find the elcetric energy consumed in the month of March.

Answer 1

let's find it in j
p= 1.6kw
t= .75 h
 E = P*t = 1.2
like this 31 days means 1.2*31= 37.2 kwh
hence 37.2 units of energy has been consumed

Answer 2

Power of electric iron = 1600 W or 1.6kw
Time=45 mins or 0.75 hrs
Now, Energy consumed = PT
= 1.6*0.75
= 1.2 kwh
Energy consumed in 1 day= 1.2 kwh
Energy consumed in month of March= 1.2*31
= 37.2 kwh or 37.2 units