Question

If an electric lamp lights for 4 hours drawing 0.8 ampere of current calculate the amount of charge that has passed through the lamp is:

Answer 1

Answer:

11520 Coulomb (or) 11520 C

Step-by-step explanation:

Given :

In an electric lamp,

• Current = 0.8 A
• Time = 4 hours

To find :

The amount of charge that has passed through the lamp

Solution :

Time = 4 hours

time in seconds will be,

we know that

$\boxed{\begin{array}{cc} \mathrm{1\ hour = 60\ minutes}\\\mathrm{1\ minute = 60 seconds}\\\mathrm{So,\ 1hour = 60 \times 60\ seconds}\\\therefore \underline{\mathrm{1\ hour = 3600\ seconds}}\end{array}}$

Thus,

4 hours = 4 × 3600 = 14400 seconds

So, time taken is 14400 seconds

We know that

$\boxed{\boxed{\begin{array}{cc}\mathrm{i = \dfrac{q}{t}}\\ \mathrm{ \implies q = i \times t}\\\text{where}\\\text{q = charge}\\\text{i = current}\\\text{t = time taken}\end{array}}}$

So, substituting the values, we get,

$\implies \mathrm{q = 0.8 \times 14400}$

$\implies \mathrm{q = 8 \times 1440}$

$\implies \mathrm{q = 11520\ C}$

Thus, the amount of charge that has passed through the lamp is 11,520 C

Hope it helps!!