If an electric motor is used to lift a mass of 8 kg a distance of 12 m in 60 seconds what was the power generated by the motor? The answer is in watts.
Answers
Answer:
what was the power generated by the motor the answer is in watts if an electric mptor is used a mass of 8 kg a distance moyor is used to loft a mass .
Answer:
At what rate do you want to lift these 100 kg? Slower the rate, lesser would be the wattage rating.
Let's do a quick calculation here:
power = work/time
work = force x distance
So power = force x distance/time or equivalently,
power = force x speed of lifting (rate)
Force needed to hold 100 kg against gravity = 100*9.8, rounding it up to 1000N.
Let's say the machine lifts it up at a rate of 1 meter per second.
So power needed would be 1000 x 1 = 1kW.
But this is the power needed without frictional and other losses. Fairly assuming that the motor and pulley assembly is 80% efficient, actual power the motor pumps in from the source would be 1000/0.8 = 1.25kW.
This verifies the aforementioned fact that higher the rate with which the weight needs to be lifted, more would be the wattage rating