Question

if an electron having charge e enters a magnetic field of induction B with velocity V the acting on it is given by F = B e V Find the dimensions of magnetic field B

Answer 1

Answer:

B = M . T^-2 . A^-1

Explanation:

given

F = evB

so

B = F/ev

F = newton

e = coloumb

v = m/s

B = newton / coloumb ×m/s

B = kg.m/S^2

-----------------

amp × m

B = kg. 1

____ × ____

S^2. A

B = kg .S^-2 . A^-1

B = M . T^-2 . A^-1