Question

If an electron is freely with 3.2

´ 10

6 ms–1 in opposite to electric field 9.1

´ 10

2NC–1. What will

be the distance covered by electron before it comes to rest ?

(A) 0.072 m (B) 0.052 m (C) 0.032 m (D) 0.016 m​

Answer 1

Answer:

Ans=c 0.032m

Explanation:

1/2MV²=qE.S     S=0.032m