If an electron is to be located within 0.2 A (2 x 10 cm), what will
be the approximate uncertainty in its velocity?
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Explanation:
According to Heisenberg's uncertainty principle:∆ו∆p=h/4pi ∆ו∆(mv)=h/4pi∆V=h/4pi∆×h=6.626×10^-34Js
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