if an elevator descends into a mine shaft at the rate of 5 metre per minute .if the descent starts from 10 m above the ground , how long will it take to reach - 440
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Answer:
In the above question the distance descended is denoted by a negative integer
It is given in the question that,
Initial height = 10 m
Also,
Final depth = - 350 m
Therefore,
Total distance to be descended by the elevator = (-350) – (10)
= - 360 m
Also,
Time taken by the elevator to descend – 6m = 1 minute
Hence,
Time taken by the elevator to descend – 360 m =
= 60 minutes
= 1 hour
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