if an elevator starts from rest
with constant downward acceleration
and cover 2.5 m in I sec. If weight
OF lift is 200kg , what would be
tension in the rope of Lift.
Answers
Answered by
1
Answer:
Tension = 1400N
Explanation:
T=m(g-a)
T=200(9.8-2.5)
T=200×7
T=1400N
Answered by
1
Answer:
that's the answer
hope it helps
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