if an empirical formula is C2H2O4 and vapour density is 180 thenbwhat it's molecular formula
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Explanation:
Emperical mass of CH
2
O = 30g
Vapour density = 90
Molecular mass = 2×90 = 180g
Therefore n =
30
180
= 6
Thus, the formula of the compound is ; (CH
2
O)
6
= C
6
H
12
O
6
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