Question

if an equilateral triangle is made of a uniform wire of resistance R, the equivalent resistance between the ends of sides is

(a).2R/3
(b).R/3
(c).2R/9
(d).9R/2

pls give the correct explanation and answer...........if i am satisfied with your correct answer I will mark you as brainliest.......
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Answer 1

Answer:

in the equilateral triangle ABC

let the resistance between AB=R1

BC=R2 , CA=R3

SO R1 AND R2 ARE CONNECTED IN SERIES

Rs= R1+R2

=2R ------------1

NOW 2R AND R3 ARE CONNECTED IN PARALLEL

Rp=2R X R/ 2R + R

=2R^2/3R

= 2R/3

Answer 2

Answer:

HOPE IT HELPS!!!

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