If an Ethernet destination address is 08:07:06:05:44:33, then this is a
A. O
multicast
B. O
unicast
C.
broadcast
D C
any of the above
Answers
Answered by
0
Answer:
the answer is nothing pdf .com for that question
Explanation:
Answered by
0
Answer:
The correct answer to the given question about an ethernet destination address which is 08:07:06:05:44:33, is found to an unicast address.
Hence option B unicast is the correct answer.
Explanation:
As per the given question,
Ethernet destination address:
- It is has six byte patterns.
- It is allocated to every hardware node / workstation.
- It has an important number since it is the only way for the hardware connected to the network to recognize other devices.
Types:
1. Unicast:
- A single LAN interface.
- Frame sent to only a specific device.
- Has MAC address of the destination device.
- Example: 08:07:06:05:44:33
2. Multicast:
- A group of devices in LAN.
- A frame sent to the multicast address then to a group of devices on the LAN.
- It has ' 1 ' as the least-significant bit of the first octet of the address.
- Example: 01:00:0C:CC:CC:CC
3. Broadcast:
- All devices on the LAN.
- Frames are sent to the broadcast address.
- Then forwarded to all devices on the LAN.
- Example: FFFF.FFFF.FFFF
To learn more about ethernet from the given links.
https://brainly.in/question/8135357
https://brainly.in/question/9744480
#SPJ6
Similar questions