English, asked by bhagyamajji2233, 5 months ago

If an Ethernet destination address is 08:07:06:05:44:33, then this is a
A. O
multicast
B. O
unicast
C.
broadcast
D C
any of the above​

Answers

Answered by selvahatch
0

Answer:

the answer is nothing pdf .com for that question

Explanation:

Answered by stalwartajk
0

Answer:

The correct answer to the given question about an ethernet destination address which is 08:07:06:05:44:33, is found to an unicast address.

Hence option B unicast is the correct answer.

Explanation:

As per the given question,

Ethernet destination address:

  1. It is has six byte patterns.
  2. It is allocated to every hardware node / workstation.
  3. It has an important number since it is the only way for the hardware connected to the network to recognize other devices.

Types:

1. Unicast:

  1. A single LAN interface.
  2. Frame sent to only a specific device.
  3. Has MAC address of the destination device.
  4. Example: 08:07:06:05:44:33

2. Multicast:

  1. A group of devices in LAN.
  2. A frame sent to the multicast address then to a group of devices on the LAN.
  3. It has ' 1 ' as the least-significant bit of the first octet of the address.
  4. Example: 01:00:0C:CC:CC:CC

3. Broadcast:

  1. All devices on the LAN.
  2. Frames are sent to the broadcast address.
  3. Then forwarded to all devices on the LAN.
  4. Example: FFFF.FFFF.FFFF

To learn more about ethernet from the given links.

https://brainly.in/question/8135357

https://brainly.in/question/9744480

#SPJ6

Similar questions