Question

If an experiment consists of five outcomes with p(o1) = 0.10, p(o2) = 0.20, p(o3) = 0.30, p(o4) = 0.25, then p(o5) is

Answer 1

There are five out comes with the probabilities as given:

$P(O_1)=0.10$, $P(O_2)=0.20$, $P(O_3)=0.30$, $P(O_4)=0.25$

We need to figure out $P(O_5)=?$

As we know that the sum of all the probabilities should be 1 therefore, we will add the probabilities of all the events and will try to find $P(O_5)$.

$P(O_1)+P(O_2)+P(O_3)+P(O_4)+P(O_5)=1$

Putting the values of all the probabilities, we get:

$0.10+0.20+0.30+0.25+P(O_5)=1$

Solving for $P(O_5)$

$0.85+P(O_5)=1$

$P(O_5)=1-(0.85)=0.15$

Therefore, $P(O_5)$=0.15.