Math, asked by arshpreetkhalsa67, 9 months ago


If an exterior angle of a triangle is 80° and its interior opposite angles are in
the ratio 3:2. Find the measure of larger angle of these interior opposite
angles.​

Answers

Answered by tanu249869
11

Answer:

exterior angle =addition of interior opposite angle

interior opp. angle are in the ratio 3:2

let the common multiple be x

80=3x+2x

80=5x

x=80/5

x=16

let one interior angle be angle A and other be B

angleA=3x=3*16=48

angle B=2*16=32

bigger angle =100

Answered by jishnu070
2

Answer:

exterior angle =addition of interior opposite angle

interior opp. angle are in the ratio 3:2

let the common multiple be x

80=3x+2x

80=5x

x=80/5

x=16

let one interior angle be angle A and other be B

angleA=3x=3*16=48

angle B=2*16=32

bigger angle =100

Step-by-step explanation:

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