If an exterior angle of a triangle is 80° and its interior opposite angles are in
the ratio 3:2. Find the measure of larger angle of these interior opposite
angles.
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Answered by
11
Answer:
exterior angle =addition of interior opposite angle
interior opp. angle are in the ratio 3:2
let the common multiple be x
80=3x+2x
80=5x
x=80/5
x=16
let one interior angle be angle A and other be B
angleA=3x=3*16=48
angle B=2*16=32
bigger angle =100
Answered by
2
Answer:
exterior angle =addition of interior opposite angle
interior opp. angle are in the ratio 3:2
let the common multiple be x
80=3x+2x
80=5x
x=80/5
x=16
let one interior angle be angle A and other be B
angleA=3x=3*16=48
angle B=2*16=32
bigger angle =100
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