if an exterior anles of a regular polygon is 45°then find the number of sides.
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sum of exterior angles of a polygon = 360°
therefore if no. of vertices is n then 45°×n = 360°
n = 360°/45° = 8
therefore the polygon has 8 vertices therefore 8 sides as well
therefore if no. of vertices is n then 45°×n = 360°
n = 360°/45° = 8
therefore the polygon has 8 vertices therefore 8 sides as well
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The polygon has 8 sides.... Please mark me as brainliest if the answer is right....
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