if an inclined plane is 2m high and its length is 5m then its inclination becomes _________
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Given:- An inclined plane which is 2m high and its length is 5m
To Find:- The inclination at which the plane is inclined
Solution:-
- we have perpendicular value i.e. 2m and hypotenuse value is 5m now we have to find the base value by using Pythagoras theorem as it is shown in the picture
(BC)^2= (AB)^2 +(AC)^2
(AB)^2= (BC)^2-(AC)^2
= (5)^2 - (2)^2
(AB)=√25-4 = √21
- Now For finding the inclination
tanФ= AC/AB
tanФ= 2/√21 = 2/4.58 = 0.436
Ф= tan^-1(0.436) = 0.411°
So the Inclination will be Ф = 0.411° Ans
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