If an individual of genotype AaBbCcDd is test crossed, how many different phenotypes can appear in the progeny?
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⚽⚽hey mate!!⚽⚽
________________________________________________________________
Answer;-256
Step by step explanations:-
Apply formula (4)^n
Where n is number of pair of heterozygous allele.
As in dihybrid cross if we apply this formula..
We get answer as....(4)^2
I.e 16
In case of tri hybrid cross....(4)^3= 64.
And so on...
In this question....
(4)4=256
Hope it will help you....
#phoenix
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