if an integer is added to its square the sum is 90 find the integer with the help of quadratic equation
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Let the integer be x.
so, square of the integer =x^2
According to question :-
x^2+x=90
x^2+x-90=0
x^2+10x-9x-90=0
x (x+10)-9 (x+10)=0
(x+10) (x-9)=0
x=-10 or x=9
Both the values are satisfying the equation (x^2+x=90) , Therefore the value of x can be both i.e. -10 and -9. ..........
hope it's
help you. .......
aparna76:
main jo answer di thi uske upar ek mark as likha hoga
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