If an integer is randomly selected from all positive 2 - digit integers, what is the probability that the integer chosen has a 4 in the tens place?
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Total no of outcomes= 90
required no. of outcomes= 10 i.e. 40, 41 , 42, _______, 49.
so,
P(E)= 10/90
= 1/9
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plz like it...
required no. of outcomes= 10 i.e. 40, 41 , 42, _______, 49.
so,
P(E)= 10/90
= 1/9
hope it helps you...
plz like it...
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