Math, asked by ridinpradeep399, 12 days ago

If an invigilator at the point I, lying on the straight line Joining B and C such that it divides the distancebetween them in the ratio of 1 :2. Then coordinates of I are *
1 point
(6,1)
(9,1)

Option 3

Option 4​

Answers

Answered by yashc26368
5

Answer:

Using the section formula, if a point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

3AC=CB

CB

AC

=

3

1

Since, A(1,1) and B(2,3) & m:n=1:3

Therefore, we have

C(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

(

1+3

(1)(2)+3(1)

,

1+3

(1)(3)+3(1)

)

C→(

4

5

,

2

3

).

Answered by GulabLachman
1

Given: An invigilator at point l lying on a straight line divides B(6,1) and C(9,1) in the ratio 1:2

To find: The coordinates of l

Explanation: For internal division of a straight line in a particular ratio, the formula used is:

( mx2+nx1/m+n, my2+ny1/m+n)

Here, l divides B(6,1) and C(9,1) in the ratio 1:2

Therefore, m=1, n=2 , x1=6, x2= 9 , y1=y2 = 1

l= ( 1*9+2*6/ 1+2, 1*1+2*1/1+2)

= (21/3, 3/3)

= (7,1)

Checking, distance of 6,1 from 7,1 = 7-6 = 1 units

Distance of 9,1 from 7,1= 9-7 = 2 units

It proves 7,1 divides 6,1 and 9,1 in 1:2.

Therefore, the coordinates of l are (7,1).

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