if an iron object is immersed in water,it displaces 8 kg of water.How much is the buoyant force acting on the iron object in Newton ?
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Given - Amount of water displaced - 8 kilogram.
Find - Buoyant force acting on the iron object in Newton .
Solution - Solving the question as per the Archimedes' principle.
Primarily, finding out the weight of water displaced. Assuming g to be 10 m/s².
Weight of water displaced = m * g, where m is mass of water and g is acceleration due to gravity.
Keeping the values in formula-
Weight = 8*10 = 80 Newton.
Now, as per the Archimedes'principle, "buoyant force is equal to the weight of the water that got displaced by the immersion of the object in it."
Therefore, buoyant force acting on the iron object in Newton is 80 N.
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