Question

if an isoceles triangle,prove that the altitude from the vertex bisect the base.the angle opposite to two equal side of a triangle are equal?​

Answer 1

Answer:

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Answer 2

Answer:

let us take a triangle ABC and draw an altitude CD

let us take a triangle ABC and draw an altitude CDbeing an isosceles triangle

let us take a triangle ABC and draw an altitude CDbeing an isosceles trianglein ΔACD and ΔCDB

let us take a triangle ABC and draw an altitude CDbeing an isosceles trianglein ΔACD and ΔCDBCD=CD (common )

let us take a triangle ABC and draw an altitude CDbeing an isosceles trianglein ΔACD and ΔCDBCD=CD (common )CA=CB ( equal opposite sides)

let us take a triangle ABC and draw an altitude CDbeing an isosceles trianglein ΔACD and ΔCDBCD=CD (common )CA=CB ( equal opposite sides)∠ A=∠ B ( angle opposite to opposite sides are also equal )

let us take a triangle ABC and draw an altitude CDbeing an isosceles trianglein ΔACD and ΔCDBCD=CD (common )CA=CB ( equal opposite sides)∠ A=∠ B ( angle opposite to opposite sides are also equal )therefore : ΔACD and ΔCDB are congruent by ASA rule

let us take a triangle ABC and draw an altitude CDbeing an isosceles trianglein ΔACD and ΔCDBCD=CD (common )CA=CB ( equal opposite sides)∠ A=∠ B ( angle opposite to opposite sides are also equal )therefore : ΔACD and ΔCDB are congruent by ASA ruleso , AD=DB by CPCT

let us take a triangle ABC and draw an altitude CDbeing an isosceles trianglein ΔACD and ΔCDBCD=CD (common )CA=CB ( equal opposite sides)∠ A=∠ B ( angle opposite to opposite sides are also equal )therefore : ΔACD and ΔCDB are congruent by ASA ruleso , AD=DB by CPCTSo, its true.

Hope you understand...