Question

If an isosceles right angled triangle has an area of 12 cm square the find the length of its base

Answer 1

Given that the triangle is isoceles right angle triangle.

For isoceles right angled triangle, the base and the height are of same length. So, let

Base = height = a

So, the area would be 1/2 × base × height

=> 1/2 × a × a

= a²/2

Given that the area is 12 cm²

=> a²/2 = 12

=> a² = 12 × 2

=> a² = 24

=> a = √24

=> a = √4 × √6

=> a = 2√6

Hence, the length of base is 2√6 cm.

Answer 2

the area is 12cm square
being rightangled and isoscaled base=height =a
we know that
area=1/2× height×base
=>area=1/2×a×a
=>12=1/2×a×a
=>1/2×a×a=12
=>a×a=12×2/1
=>a=square root 24
as base=height
then ,
square root24/2=sqare root6cm
base=square root6
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