If an isosceles right angled triangle has an area of 12cm2, then ,find the length of its base.
Answers
Answered by
1
In an isosceles triangle two sides are equal.
Here the base and the perpendicular of the triangle are equal in length.
Area of the triangle=12cm^2
12cm^2 =1/2*base*height
Put b & h as x
24=x^2
X =4.899cm..
So, length of its base is 4.899 cm
Here the base and the perpendicular of the triangle are equal in length.
Area of the triangle=12cm^2
12cm^2 =1/2*base*height
Put b & h as x
24=x^2
X =4.899cm..
So, length of its base is 4.899 cm
Similar questions